motheboss356
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gotta have this finished in an hour and idk how to do this help

Your parents have finally decided to install an in-ground pool! They come to you for help. They are deciding between a circular pool with a 30-foot diameter and a 16 ft x 40 ft rectangular pool. The circular pool would have a 4-foot walkway all the way around it, and the rectangular pool would have a 3-foot walkway all the way around it. The backyard measures 75 feet by 50 feet.

Calculations for the area of the circular pool with the 4-foot walkway.
Calculations for the area of the rectangular pool with the 3-foot walkway.
Calculations for determining how much grassy area is available with the circular pool.
Calculations for determining how much grassy area is available with the rectangular pool.

Respuesta :

twvogels
[tex]Area_{circle}=\pi r^{2}[/tex]
[tex]Area_{circle} = \pi (pool+walkway)^{2}[/tex]
[tex]Area_{circle} = \pi (\frac{30}{2}+4)^{2}[/tex]
[tex]Area_{circle} = \pi (19)^{2}[/tex]
[tex]Area_{circle} = \pi (19)^{2}=361 \pi \approx 1134.11[/tex]

[tex]Area_{rectangle}=lw[/tex]
[tex]Area_{rectangle}=(l_{pool}+2(walkway))\times(w_{pool}+2(walkway))[/tex]
[tex]Area_{rectangle}=(16+2(3))\times(40+2(3))[/tex]
[tex]Area_{rectangle}=22\times46[/tex]
[tex]Area_{rectangle}=1012[/tex]

[tex]Area_{yard}=lw=75\times50=3750[/tex]

With round:
[tex]Area_{GrassAvailable}=A_{yard}-A_{circle}[/tex]
[tex]Area_{GrassAvailable}=3750-1134.11=2615.89[/tex]

With rectangle:
[tex]Area_{GrassAvailable}=A_{yard}-A_{rectangle}[/tex]
[tex]Area_{GrassAvailable}=3750-1012=2738[/tex]

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