Find the first, fourth, and eighth terms of the sequence. A(n)= -2 x 5^n-1

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04-08-2017
Mathematics

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Find the first, fourth, and eighth terms of the sequence. A(n)= -2 x 5^n-1

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All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

What value of x makes the equation true ? 4(2x-4)=16

All of the following expressions have a value between 0 and 1, excepta. \frac{(-3^{7})}{(-3)^9}b. 4^{-10}× 4^{6}c. \frac{(8^3)^3}{8^{-4}} d. ( \frac{2}{5} ^{8})

What value of x makes the equation true ? 4(2x-4)=16

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apologiabiology apologiabiology · Answer 1 · 2017-08-04T01:12:18+02:00

apologiabiology apologiabiology

04-08-2017

you've got
[tex]A(n)=-2(5)^{n-1}[/tex]

just sub the number of the term to findd the term
first term is A(1)=-2(5)^(1-1)=-2(5)^0=-2(1)=-2
4th is A(4)=-2(5)^(4-1)=-2(5)^3=-2(125)=-250
8th term is A(8)=-2(5)^(8-1)=-2(5)^7=-2(78125)=-156250

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